Optimal. Leaf size=316 \[ -\frac{9 a^{5/4} d^{11/2} \log \left (-\sqrt{2} \sqrt [4]{a} \sqrt [4]{b} \sqrt{d x}+\sqrt{a} \sqrt{d}+\sqrt{b} \sqrt{d} x\right )}{8 \sqrt{2} b^{13/4}}+\frac{9 a^{5/4} d^{11/2} \log \left (\sqrt{2} \sqrt [4]{a} \sqrt [4]{b} \sqrt{d x}+\sqrt{a} \sqrt{d}+\sqrt{b} \sqrt{d} x\right )}{8 \sqrt{2} b^{13/4}}-\frac{9 a^{5/4} d^{11/2} \tan ^{-1}\left (1-\frac{\sqrt{2} \sqrt [4]{b} \sqrt{d x}}{\sqrt [4]{a} \sqrt{d}}\right )}{4 \sqrt{2} b^{13/4}}+\frac{9 a^{5/4} d^{11/2} \tan ^{-1}\left (\frac{\sqrt{2} \sqrt [4]{b} \sqrt{d x}}{\sqrt [4]{a} \sqrt{d}}+1\right )}{4 \sqrt{2} b^{13/4}}-\frac{9 a d^5 \sqrt{d x}}{2 b^3}-\frac{d (d x)^{9/2}}{2 b \left (a+b x^2\right )}+\frac{9 d^3 (d x)^{5/2}}{10 b^2} \]
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Rubi [A] time = 0.383407, antiderivative size = 316, normalized size of antiderivative = 1., number of steps used = 14, number of rules used = 10, integrand size = 28, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.357, Rules used = {28, 288, 321, 329, 211, 1165, 628, 1162, 617, 204} \[ -\frac{9 a^{5/4} d^{11/2} \log \left (-\sqrt{2} \sqrt [4]{a} \sqrt [4]{b} \sqrt{d x}+\sqrt{a} \sqrt{d}+\sqrt{b} \sqrt{d} x\right )}{8 \sqrt{2} b^{13/4}}+\frac{9 a^{5/4} d^{11/2} \log \left (\sqrt{2} \sqrt [4]{a} \sqrt [4]{b} \sqrt{d x}+\sqrt{a} \sqrt{d}+\sqrt{b} \sqrt{d} x\right )}{8 \sqrt{2} b^{13/4}}-\frac{9 a^{5/4} d^{11/2} \tan ^{-1}\left (1-\frac{\sqrt{2} \sqrt [4]{b} \sqrt{d x}}{\sqrt [4]{a} \sqrt{d}}\right )}{4 \sqrt{2} b^{13/4}}+\frac{9 a^{5/4} d^{11/2} \tan ^{-1}\left (\frac{\sqrt{2} \sqrt [4]{b} \sqrt{d x}}{\sqrt [4]{a} \sqrt{d}}+1\right )}{4 \sqrt{2} b^{13/4}}-\frac{9 a d^5 \sqrt{d x}}{2 b^3}-\frac{d (d x)^{9/2}}{2 b \left (a+b x^2\right )}+\frac{9 d^3 (d x)^{5/2}}{10 b^2} \]
Antiderivative was successfully verified.
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Rule 28
Rule 288
Rule 321
Rule 329
Rule 211
Rule 1165
Rule 628
Rule 1162
Rule 617
Rule 204
Rubi steps
\begin{align*} \int \frac{(d x)^{11/2}}{a^2+2 a b x^2+b^2 x^4} \, dx &=b^2 \int \frac{(d x)^{11/2}}{\left (a b+b^2 x^2\right )^2} \, dx\\ &=-\frac{d (d x)^{9/2}}{2 b \left (a+b x^2\right )}+\frac{1}{4} \left (9 d^2\right ) \int \frac{(d x)^{7/2}}{a b+b^2 x^2} \, dx\\ &=\frac{9 d^3 (d x)^{5/2}}{10 b^2}-\frac{d (d x)^{9/2}}{2 b \left (a+b x^2\right )}-\frac{\left (9 a d^4\right ) \int \frac{(d x)^{3/2}}{a b+b^2 x^2} \, dx}{4 b}\\ &=-\frac{9 a d^5 \sqrt{d x}}{2 b^3}+\frac{9 d^3 (d x)^{5/2}}{10 b^2}-\frac{d (d x)^{9/2}}{2 b \left (a+b x^2\right )}+\frac{\left (9 a^2 d^6\right ) \int \frac{1}{\sqrt{d x} \left (a b+b^2 x^2\right )} \, dx}{4 b^2}\\ &=-\frac{9 a d^5 \sqrt{d x}}{2 b^3}+\frac{9 d^3 (d x)^{5/2}}{10 b^2}-\frac{d (d x)^{9/2}}{2 b \left (a+b x^2\right )}+\frac{\left (9 a^2 d^5\right ) \operatorname{Subst}\left (\int \frac{1}{a b+\frac{b^2 x^4}{d^2}} \, dx,x,\sqrt{d x}\right )}{2 b^2}\\ &=-\frac{9 a d^5 \sqrt{d x}}{2 b^3}+\frac{9 d^3 (d x)^{5/2}}{10 b^2}-\frac{d (d x)^{9/2}}{2 b \left (a+b x^2\right )}+\frac{\left (9 a^{3/2} d^4\right ) \operatorname{Subst}\left (\int \frac{\sqrt{a} d-\sqrt{b} x^2}{a b+\frac{b^2 x^4}{d^2}} \, dx,x,\sqrt{d x}\right )}{4 b^2}+\frac{\left (9 a^{3/2} d^4\right ) \operatorname{Subst}\left (\int \frac{\sqrt{a} d+\sqrt{b} x^2}{a b+\frac{b^2 x^4}{d^2}} \, dx,x,\sqrt{d x}\right )}{4 b^2}\\ &=-\frac{9 a d^5 \sqrt{d x}}{2 b^3}+\frac{9 d^3 (d x)^{5/2}}{10 b^2}-\frac{d (d x)^{9/2}}{2 b \left (a+b x^2\right )}-\frac{\left (9 a^{5/4} d^{11/2}\right ) \operatorname{Subst}\left (\int \frac{\frac{\sqrt{2} \sqrt [4]{a} \sqrt{d}}{\sqrt [4]{b}}+2 x}{-\frac{\sqrt{a} d}{\sqrt{b}}-\frac{\sqrt{2} \sqrt [4]{a} \sqrt{d} x}{\sqrt [4]{b}}-x^2} \, dx,x,\sqrt{d x}\right )}{8 \sqrt{2} b^{13/4}}-\frac{\left (9 a^{5/4} d^{11/2}\right ) \operatorname{Subst}\left (\int \frac{\frac{\sqrt{2} \sqrt [4]{a} \sqrt{d}}{\sqrt [4]{b}}-2 x}{-\frac{\sqrt{a} d}{\sqrt{b}}+\frac{\sqrt{2} \sqrt [4]{a} \sqrt{d} x}{\sqrt [4]{b}}-x^2} \, dx,x,\sqrt{d x}\right )}{8 \sqrt{2} b^{13/4}}+\frac{\left (9 a^{3/2} d^6\right ) \operatorname{Subst}\left (\int \frac{1}{\frac{\sqrt{a} d}{\sqrt{b}}-\frac{\sqrt{2} \sqrt [4]{a} \sqrt{d} x}{\sqrt [4]{b}}+x^2} \, dx,x,\sqrt{d x}\right )}{8 b^{7/2}}+\frac{\left (9 a^{3/2} d^6\right ) \operatorname{Subst}\left (\int \frac{1}{\frac{\sqrt{a} d}{\sqrt{b}}+\frac{\sqrt{2} \sqrt [4]{a} \sqrt{d} x}{\sqrt [4]{b}}+x^2} \, dx,x,\sqrt{d x}\right )}{8 b^{7/2}}\\ &=-\frac{9 a d^5 \sqrt{d x}}{2 b^3}+\frac{9 d^3 (d x)^{5/2}}{10 b^2}-\frac{d (d x)^{9/2}}{2 b \left (a+b x^2\right )}-\frac{9 a^{5/4} d^{11/2} \log \left (\sqrt{a} \sqrt{d}+\sqrt{b} \sqrt{d} x-\sqrt{2} \sqrt [4]{a} \sqrt [4]{b} \sqrt{d x}\right )}{8 \sqrt{2} b^{13/4}}+\frac{9 a^{5/4} d^{11/2} \log \left (\sqrt{a} \sqrt{d}+\sqrt{b} \sqrt{d} x+\sqrt{2} \sqrt [4]{a} \sqrt [4]{b} \sqrt{d x}\right )}{8 \sqrt{2} b^{13/4}}+\frac{\left (9 a^{5/4} d^{11/2}\right ) \operatorname{Subst}\left (\int \frac{1}{-1-x^2} \, dx,x,1-\frac{\sqrt{2} \sqrt [4]{b} \sqrt{d x}}{\sqrt [4]{a} \sqrt{d}}\right )}{4 \sqrt{2} b^{13/4}}-\frac{\left (9 a^{5/4} d^{11/2}\right ) \operatorname{Subst}\left (\int \frac{1}{-1-x^2} \, dx,x,1+\frac{\sqrt{2} \sqrt [4]{b} \sqrt{d x}}{\sqrt [4]{a} \sqrt{d}}\right )}{4 \sqrt{2} b^{13/4}}\\ &=-\frac{9 a d^5 \sqrt{d x}}{2 b^3}+\frac{9 d^3 (d x)^{5/2}}{10 b^2}-\frac{d (d x)^{9/2}}{2 b \left (a+b x^2\right )}-\frac{9 a^{5/4} d^{11/2} \tan ^{-1}\left (1-\frac{\sqrt{2} \sqrt [4]{b} \sqrt{d x}}{\sqrt [4]{a} \sqrt{d}}\right )}{4 \sqrt{2} b^{13/4}}+\frac{9 a^{5/4} d^{11/2} \tan ^{-1}\left (1+\frac{\sqrt{2} \sqrt [4]{b} \sqrt{d x}}{\sqrt [4]{a} \sqrt{d}}\right )}{4 \sqrt{2} b^{13/4}}-\frac{9 a^{5/4} d^{11/2} \log \left (\sqrt{a} \sqrt{d}+\sqrt{b} \sqrt{d} x-\sqrt{2} \sqrt [4]{a} \sqrt [4]{b} \sqrt{d x}\right )}{8 \sqrt{2} b^{13/4}}+\frac{9 a^{5/4} d^{11/2} \log \left (\sqrt{a} \sqrt{d}+\sqrt{b} \sqrt{d} x+\sqrt{2} \sqrt [4]{a} \sqrt [4]{b} \sqrt{d x}\right )}{8 \sqrt{2} b^{13/4}}\\ \end{align*}
Mathematica [A] time = 0.319475, size = 235, normalized size = 0.74 \[ \frac{d^5 \sqrt{d x} \left (\frac{8 \sqrt [4]{b} \sqrt{x} \left (-45 a^2-36 a b x^2+4 b^2 x^4\right )}{a+b x^2}-45 \sqrt{2} a^{5/4} \log \left (-\sqrt{2} \sqrt [4]{a} \sqrt [4]{b} \sqrt{x}+\sqrt{a}+\sqrt{b} x\right )+45 \sqrt{2} a^{5/4} \log \left (\sqrt{2} \sqrt [4]{a} \sqrt [4]{b} \sqrt{x}+\sqrt{a}+\sqrt{b} x\right )-90 \sqrt{2} a^{5/4} \tan ^{-1}\left (1-\frac{\sqrt{2} \sqrt [4]{b} \sqrt{x}}{\sqrt [4]{a}}\right )+90 \sqrt{2} a^{5/4} \tan ^{-1}\left (\frac{\sqrt{2} \sqrt [4]{b} \sqrt{x}}{\sqrt [4]{a}}+1\right )\right )}{80 b^{13/4} \sqrt{x}} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.088, size = 242, normalized size = 0.8 \begin{align*}{\frac{2\,{d}^{3}}{5\,{b}^{2}} \left ( dx \right ) ^{{\frac{5}{2}}}}-4\,{\frac{a{d}^{5}\sqrt{dx}}{{b}^{3}}}-{\frac{{d}^{7}{a}^{2}}{2\,{b}^{3} \left ( b{d}^{2}{x}^{2}+a{d}^{2} \right ) }\sqrt{dx}}+{\frac{9\,a{d}^{5}\sqrt{2}}{16\,{b}^{3}}\sqrt [4]{{\frac{a{d}^{2}}{b}}}\ln \left ({ \left ( dx+\sqrt [4]{{\frac{a{d}^{2}}{b}}}\sqrt{dx}\sqrt{2}+\sqrt{{\frac{a{d}^{2}}{b}}} \right ) \left ( dx-\sqrt [4]{{\frac{a{d}^{2}}{b}}}\sqrt{dx}\sqrt{2}+\sqrt{{\frac{a{d}^{2}}{b}}} \right ) ^{-1}} \right ) }+{\frac{9\,a{d}^{5}\sqrt{2}}{8\,{b}^{3}}\sqrt [4]{{\frac{a{d}^{2}}{b}}}\arctan \left ({\sqrt{2}\sqrt{dx}{\frac{1}{\sqrt [4]{{\frac{a{d}^{2}}{b}}}}}}+1 \right ) }+{\frac{9\,a{d}^{5}\sqrt{2}}{8\,{b}^{3}}\sqrt [4]{{\frac{a{d}^{2}}{b}}}\arctan \left ({\sqrt{2}\sqrt{dx}{\frac{1}{\sqrt [4]{{\frac{a{d}^{2}}{b}}}}}}-1 \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.40033, size = 636, normalized size = 2.01 \begin{align*} \frac{180 \, \left (-\frac{a^{5} d^{22}}{b^{13}}\right )^{\frac{1}{4}}{\left (b^{4} x^{2} + a b^{3}\right )} \arctan \left (-\frac{\left (-\frac{a^{5} d^{22}}{b^{13}}\right )^{\frac{3}{4}} \sqrt{d x} a b^{10} d^{5} - \left (-\frac{a^{5} d^{22}}{b^{13}}\right )^{\frac{3}{4}} \sqrt{a^{2} d^{11} x + \sqrt{-\frac{a^{5} d^{22}}{b^{13}}} b^{6}} b^{10}}{a^{5} d^{22}}\right ) + 45 \, \left (-\frac{a^{5} d^{22}}{b^{13}}\right )^{\frac{1}{4}}{\left (b^{4} x^{2} + a b^{3}\right )} \log \left (9 \, \sqrt{d x} a d^{5} + 9 \, \left (-\frac{a^{5} d^{22}}{b^{13}}\right )^{\frac{1}{4}} b^{3}\right ) - 45 \, \left (-\frac{a^{5} d^{22}}{b^{13}}\right )^{\frac{1}{4}}{\left (b^{4} x^{2} + a b^{3}\right )} \log \left (9 \, \sqrt{d x} a d^{5} - 9 \, \left (-\frac{a^{5} d^{22}}{b^{13}}\right )^{\frac{1}{4}} b^{3}\right ) + 4 \,{\left (4 \, b^{2} d^{5} x^{4} - 36 \, a b d^{5} x^{2} - 45 \, a^{2} d^{5}\right )} \sqrt{d x}}{40 \,{\left (b^{4} x^{2} + a b^{3}\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (d x\right )^{\frac{11}{2}}}{\left (a + b x^{2}\right )^{2}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.16369, size = 406, normalized size = 1.28 \begin{align*} -\frac{1}{80} \,{\left (\frac{40 \, \sqrt{d x} a^{2} d^{3}}{{\left (b d^{2} x^{2} + a d^{2}\right )} b^{3}} - \frac{90 \, \sqrt{2} \left (a b^{3} d^{2}\right )^{\frac{1}{4}} a d \arctan \left (\frac{\sqrt{2}{\left (\sqrt{2} \left (\frac{a d^{2}}{b}\right )^{\frac{1}{4}} + 2 \, \sqrt{d x}\right )}}{2 \, \left (\frac{a d^{2}}{b}\right )^{\frac{1}{4}}}\right )}{b^{4}} - \frac{90 \, \sqrt{2} \left (a b^{3} d^{2}\right )^{\frac{1}{4}} a d \arctan \left (-\frac{\sqrt{2}{\left (\sqrt{2} \left (\frac{a d^{2}}{b}\right )^{\frac{1}{4}} - 2 \, \sqrt{d x}\right )}}{2 \, \left (\frac{a d^{2}}{b}\right )^{\frac{1}{4}}}\right )}{b^{4}} - \frac{45 \, \sqrt{2} \left (a b^{3} d^{2}\right )^{\frac{1}{4}} a d \log \left (d x + \sqrt{2} \left (\frac{a d^{2}}{b}\right )^{\frac{1}{4}} \sqrt{d x} + \sqrt{\frac{a d^{2}}{b}}\right )}{b^{4}} + \frac{45 \, \sqrt{2} \left (a b^{3} d^{2}\right )^{\frac{1}{4}} a d \log \left (d x - \sqrt{2} \left (\frac{a d^{2}}{b}\right )^{\frac{1}{4}} \sqrt{d x} + \sqrt{\frac{a d^{2}}{b}}\right )}{b^{4}} - \frac{32 \,{\left (\sqrt{d x} b^{8} d^{6} x^{2} - 10 \, \sqrt{d x} a b^{7} d^{6}\right )}}{b^{10} d^{5}}\right )} d^{4} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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